Video 1:
From that video, I think that we have to believe with our ability. We have to certain that we be able to doing something. If we have a dream, so we must sure that we can to reach our dream. Without assureance from our heart, we incable to doing we anxious and we dream. So, we must believe with our ability.
Video 2:
In second video, I am more know about mathematics. Mathematics learned geometry, trigonometry, ln x, significant figure, limit x approach boundlessly, exponent, integral e power x and from this video, I know that value of phi is 3,145…………
Video 3:
The third video show about mathematic problem solving.
For example :
The graph of f(x) = x + 1 if 2f(p) = 20. How value of f(3p)?
Answer:
2f(p) = 20
f(p) = 10
f(x) = x + 1
we substitution p to f(x) = x + 1 become f(p) = p + 1
f(p) = p + 1 = 10
p = 10 – 1 = 9
f(3p)????
3p = 3(9) = 27
f(x) = x + 1
f(3p) = 3p + 1 = 27 + 1 = 28
So value of f(3p) is 28
Video 4:
Video 4 about the properties of logarithm.
1. Log x to the base b equals y symmetry with b power y equal x
2. Log x to the base 10 equals Log x
3. Log x to the base natural numeral equasl Ln x (this natural logarithm)
Example :
1.Log 100 to the base 10 equals x. How value of x?
2. Log x to the base 2 equasl 3. How value of x?
3. Log 1 over 49 to the base 7 equals x. How value of x?
Answer :
1. Log 100 to the base 10 equals x, become 10 to the power of x equals 100, so x equal 2.
2. Log x to the base 2 equals 3, become 2 to the power of 3 equal x, so x equals 8.
3. Log 1 over 49 to the base 7 equals x, become 7 to the power of x equals 1 over 7 to the power of 2 in bracket. This similer with 7 to the power of x equals 7 to the power of minus 2, so x equal minus 2.
4. Log M times N in bracket to the base b equals Log M to the base 2 plus Log N to the base 2.
5. Log M over N in bracket to the base b equals Log m to the base 2 minus Log N to the base 2.
6. Log x to the power of n in bracket to the base b equals n times Log x to the base b.
Example:
How value of Log x to the power of 2 times y plus 1 in bracket all over open bracket z to the power of 3 close bracket in square bracket to the base 3?
Answer:
Log x to the power of 2 times y plus 1 in bracket all over open bracket z to the power of 3 close bracket in bracket to the base 3
equals Log x to the power 2 times open bracket y plus 1 close bracket in square bracket to the base 3 minus Log z to the power 3 in bracket to the base 3
equals Log x to the power 2 to the base 3 plus Log open bracket y plus 1 close bracket to the base 3 minus Log z to the power 3 to the base 3
equals 2 times Log x to the base 3 plus Log y plus 1 in bracket to the base 3 minus 3 times Log z to the base 3.
So, Log x to the power of 2 times y plus 1 in bracket over open bracket z to the power of 3 close bracket in bracket to the base 3 equals 2 times Log x to the base 3 plus Log y plus 1 in bracket to the base 3 minus 3 times Log z to the base 3.
Video 5:
About Graph of Rational Function.
Example:
Draw a function of f(x) equals x plus 2 in bracket over x minus 1 in bracket
Answer:
f(x) = ( x + 2 ) / ( x – 1 )
even x = 1 we find f (x) = 3 / 0 ( this wrong and imposible ), so graph of f(x) not be able nudge line x = 1.
And not all rational fuction denominator can be zero..
Video 6:
Video 6 consist obout Trigonometry.
Sine (Sin), Cosine (Cos), and Tangents (Tan) are trigonometric ratios.
Ratio of Sin is opposite per hypotenuse (soh)
Ratio of
Ratio of Tan is opposite per adjoin (toa)
The other trigomometric rations are represented as follows:
Secant (Sec) is one cos
Cosecant (Cos) is one sin
Cotangents (Cot) is one tan
For example:
If the right triangle ABC right angled at B where AB = 3 cm, BC = 4 cm, CA = 5 cm (hypotenuse). P is angle front of BC and Q is front of BA. How value of all trigonometric ratio?
Answer:
1. Sin P = opposite/hypotenuse = 4/5
Cos P = adjoin/hypotenuse = 3/ 5
Tan P = opposite/ adjoin = 4 /3
Cosec P = one sin = 5/ 4
Sec P = one cos =5/ 3
Cot P = one tan = 3/ 4
2. Sin Q = opposite/ hypotenuse =3/ 5
Cos Q = adjoin/ hypotenuse = 4/ 5
Tan Q = opposite/ adjoin = 3/ 4
Cosec Q = one sin = 5/ 3
Sec Q = one cos = 5 /4
Cot Q = one tan =4/ 3